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# $lim_{n→∞}(1−n_{2}1 +1−n_{2}2 +⋯+1−n_{2}n )$ is equal to

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## Text solutionVerified

$=∴= (1−n_{2}1 +1−n_{2}2 +⋯+1−n_{2}n )=1−n_{2}1 ×(1+2+...+n)1−n_{2}1 ⋅2n(n+1) =2(1−n)n =2[(1/n)−1]1 n→∞lim (1−n_{2}1 +1−n_{2}2 +⋯+1−n_{2}n )n→∞lim 2[(1/n)−1]1 =−21 . $

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**LIVE**classesQuestion Text | $lim_{n→∞}(1−n_{2}1 +1−n_{2}2 +⋯+1−n_{2}n )$ is equal to |

Updated On | Apr 10, 2022 |

Topic | Limits and Derivatives |

Subject | Mathematics |

Class | Class 11 |

Answer Type | Text solution:1 Video solution: 1 |

Upvotes | 222 |

Avg. Video Duration | 18 min |